Given a sorted array of_n_integers, find the starting and ending position of a given target value.
If the target is not found in the array, return[-1, -1].
Have you met this question in a real interview?
Yes
Example
Given[5, 7, 7, 8, 8, 10]and target value8,
return[3, 4].
- binary search to find the left bound and right bound
public class Solution {
/**
*@param A : an integer sorted array
*@param target : an integer to be inserted
*return : a list of length 2, [index1, index2]
*/
public int[] searchRange(int[] A, int target) {
// write your code here
int[] ans = new int[2];
ans[0] = -1;
ans[1] = -1;
if (A == null || A.length == 0) {
return ans;
}
//find first
ans[0] = findFirst(A, target);
if (ans[0] == -1) {
return ans;
}
ans[1] = findLast(A, target);
return ans;
}
public int findFirst(int[] A, int target) {
int start = 0;
int end = A.length - 1;
while (start + 1 < end) {
int mid = start + (end - start) / 2;
if (A[mid] > target) {
end = mid;
} else if (A[mid] == target) {
end = mid;
} else {
start = mid;
}
}
if (A[start] == target) {
return start;
} else if (A[end] == target) {
return end;
}
return -1;
}
public int findLast(int[] A, int target) {
int start = 0;
int end = A.length - 1;
while (start + 1 < end) {
int mid = start + (end - start) / 2;
if (A[mid] > target) {
end = mid;
} else if (A[mid] == target) {
start = mid;
} else {
start = mid;
}
}
if (A[end] == target) {
return end;
} else if (A[start] == target) {
return start;
}
return -1;
}
}