The structure of Segment Tree is a binary tree which each node has two attributesstartandenddenote an segment / interval.
_start_and_end_are both integers, they should be assigned in following rules:
- The root's
start
and
end
is given by
buildmethod. - The left child of node A has
start=A.left, end=(A.left + A.right) / 2. - The right child of node A has
start=(A.left + A.right) / 2 + 1, end=A.right. - if start equals to end , there will be no children for this node.
Implement abuildmethod with a given array, so that we can create a corresponding segment tree with every node value represent the corresponding interval max value in the array, return the root of this segment tree.
Have you met this question in a real interview?
Yes
Clarification
Segment Tree (a.k.a Interval Tree) is an advanced data structure which can support queries like:
- which of these intervals contain a given point
- which of these points are in a given interval
See wiki:
Segment Tree
Interval Tree
Example
Given[3,2,1,4]. The segment tree will be:
[0, 3] (max = 4)
/ \
[0, 1] (max = 3) [2, 3] (max = 4)
/ \ / \
[0, 0](max = 3) [1, 1](max = 2)[2, 2](max = 1) [3, 3] (max = 4)
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/**
* Definition of SegmentTreeNode:
* public class SegmentTreeNode {
* public int start, end, max;
* public SegmentTreeNode left, right;
* public SegmentTreeNode(int start, int end, int max) {
* this.start = start;
* this.end = end;
* this.max = max
* this.left = this.right = null;
* }
* }
*/
public class Solution {
/*
* @param A: a list of integer
* @return: The root of Segment Tree
*/
public SegmentTreeNode build(int[] A) {
// write your code here
if (A == null || A.length == 0) {
return null;
}
return divideConquer(A, 0, A.length - 1);
}
public SegmentTreeNode divideConquer(int[] A, int start, int end) {
//exit
if (start == end) {
return new SegmentTreeNode(start, start, A[start]);
}
SegmentTreeNode root = new SegmentTreeNode(start, end, 0);
int mid = (start + end) / 2;
SegmentTreeNode left = divideConquer(A, start, mid);
SegmentTreeNode right = divideConquer(A, mid + 1, end);
root.left = left;
root.right = right;
root.max = Math.max(left.max, right.max);
return root;
}
}